Both require exactly floor(log2(n)) + 1 comparisons in the worst case, as Eytzinger is just a different memory layout of the same binary search tree. The performance difference comes from cache behavior, not comparison count. Eytzinger's advantage is that frequently accessed nodes near the root are cached together, not fewer comparisons.
Tree Data Structures Optimization FAQ & Answers
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Cache-Efficient Tree Layouts (van Emde Boas, B-heap)
14 questionsSorted array binary search incurs approximately log2(n) cache misses for large arrays, as each comparison likely accesses a different cache line. Eytzinger layout reduces this to approximately log2(n) / log2(B) misses, where B is elements per cache line, because B levels fit in one cache line at the top of the tree. For 64-byte lines with 8-byte elements, this is roughly 3x fewer misses.
The van Emde Boas (vEB) layout is a recursive memory layout for trees where the tree is cut at half its height, storing the top subtree followed by all bottom subtrees contiguously. This ensures that any root-to-leaf path touches only O(log_B N) cache lines, where B is the cache line size. The layout is cache-oblivious, meaning it performs optimally without knowing cache parameters.
Searching in a van Emde Boas layout tree requires O(log_B N) memory transfers, where B is the block/cache line size and N is the number of elements. This is asymptotically optimal for comparison-based searching. For example, with 64-byte cache lines holding 8 integers each, searching 1 million elements requires about log_8(1000000) = 7 cache line accesses.
The Eytzinger layout stores array elements in breadth-first (level-order) traversal order of a complete binary search tree, with the root at index 1. Unlike a sorted array where binary search jumps unpredictably, Eytzinger layout places frequently accessed nodes (near root) at the beginning of the array, improving cache locality. Navigation uses k = 2k for left child and k = 2k+1 for right child.
Eytzinger layout achieves 4-5x speedup over std::lower_bound for large arrays. At around 16K elements, branchless Eytzinger can be up to 3x faster. The maximum observed speedup is about 2x for very large arrays (268 million elements). Performance gains come from better cache utilization and predictable memory access patterns that enable effective prefetching.
A B-heap is a binary heap that lays out subtrees to fit within single memory pages, reducing page faults during traversal. Traditional heaps scatter nodes across pages because distance to children doubles at each level. B-heaps can be up to 10x faster for large heaps by reducing page misses from one per level to one per several levels of traversal.
Use van Emde Boas layout when array size significantly exceeds L2 cache (typically >256KB) and when queries span multiple cache levels. Eytzinger is better for arrays fitting in L2 cache due to simpler implementation. Van Emde Boas excels in hierarchical memory systems with multiple cache levels, while Eytzinger is optimal for single-level cache optimization with its simpler navigation formulas.
A cache-oblivious B-tree achieves O(log_B N) memory transfers for search without knowing the cache line size B at compile time. Use it when your code must run efficiently across different hardware with varying cache parameters, or when dealing with multi-level memory hierarchies. It performs within a constant factor of cache-aware B-trees while requiring no tuning.
Cache-efficient layouts for Bounding Volume Hierarchies (BVH) provide 26% to 2600% performance improvement depending on the workload. For ray tracing and collision detection, the improvement comes from exploiting access pattern localities typical of BVH applications. Static van Emde Boas construction is particularly effective because BVH traversal has predictable access patterns.
Cache-sensitive layouts consistently improve search performance of large AVL and red-black trees by 26-32% compared to pointer-based layouts. This improvement holds for both synthetic benchmarks and realistic search tree operations extracted from database workloads. The gain comes from better spatial locality when traversing from root to leaf.
Choose branching factor B such that a node fits in one cache line. For 64-byte cache lines with 8-byte keys and 8-byte pointers: B keys and B+1 pointers need 8B + 8(B+1) = 16B + 8 bytes, so B = 3 (56 bytes). For 4-byte keys/pointers: 4B + 4(B+1) = 8B + 4, so B = 7 (60 bytes). Maximize B while staying under cache line size.
In Eytzinger layout, prefetch the cache line containing indices 2k and 2k+1 (both children) with a single prefetch since they are adjacent. For deeper lookahead, prefetch the cache line containing indices 16k to 16k+15, which are the nodes needed 4 iterations ahead. This hides memory latency by initiating fetches before they are needed.
To build Eytzinger layout from sorted array: recursively place median at current position, then place left half's median at 2pos and right half's median at 2pos+1. For direct conversion, use: eytzinger_index = 1; for each bit of sorted_index from MSB, go left (2x) or right (2x+1). The process is essentially building a BST in BFS order.
Tree Serialization for Performance
11 questionsBoth serialization and deserialization run in O(n) time, visiting each node exactly once. Serialization performs a preorder traversal writing node values and null markers. Deserialization reads the sequence linearly, reconstructing nodes in the same order. Space complexity is also O(n) for storing the serialized sequence, with null markers adding at most O(n) overhead.
A BST can be serialized using only preorder or postorder traversal without null markers because the BST property allows unique reconstruction. During deserialization, each value's position is determined by comparing with ancestors to decide left or right placement. This reduces serialized size by eliminating 2n null markers, roughly halving the output size.
Inorder traversal visits left subtree, root, then right subtree, making it impossible to identify the root's position in the serialized sequence without additional information. The root appears somewhere in the middle, but its exact position depends on subtree sizes. Preorder or postorder work because they visit the root first or last, providing an anchor point for reconstruction.
LOUDS (Level-Order Unary Degree Sequence) represents a tree by traversing in breadth-first order, writing a 1-bit followed by as many 0-bits as each node has children. It uses 2n + o(n) bits for an n-node tree, which is within o(n) bits of the information-theoretic minimum. All navigation operations run in O(1) time on the RAM model.
Both use 2n + o(n) bits, but balanced parentheses (BP) is generally superior in practice. BP writes open parenthesis when first visiting a node and close parenthesis when leaving during preorder traversal. BP provides an excellent combination of space, time performance, and functionality, while LOUDS is competitive only in limited-functionality scenarios requiring specific operations.
Pointer-based trees use O(n log n) bits (typically 2-3 pointers per node, each log n bits for addressing). Succinct representations use only 2n + o(n) bits, achieving near information-theoretic minimum. For a tree with 1 million nodes, pointers need roughly 64-96 MB (64-bit pointers) while succinct needs only about 250 KB, a 256-384x reduction.
DFS uses O(maxDepth) memory for the call stack or explicit stack, while BFS uses O(maxWidth) memory for the queue. For balanced trees, width grows exponentially (2^h at depth h), so BFS uses more memory. For deep narrow trees, DFS uses more. In practice, most trees are wider than deep, making DFS more memory-efficient.
Use level-order (BFS) serialization when: (1) deserializing into cache-efficient layouts like Eytzinger that store nodes in BFS order, (2) the tree is complete and null markers can be omitted, (3) you need to reconstruct nodes level-by-level for streaming. Use preorder for BSTs (no null markers needed) or when recursive deserialization is simpler.
DFUDS (Depth-First Unary Degree Sequence) encodes nodes during depth-first traversal by writing the degree in unary (d ones followed by a zero) when first visiting each node. LOUDS uses breadth-first order. Both use 2n + o(n) bits. DFUDS supports efficient subtree operations due to DFS ordering, while LOUDS excels at level-order operations and sibling navigation.
Succinct tree representations support parent, left-child, right-child, subtree-size, level-ancestor, lowest-common-ancestor (LCA), and depth queries in O(1) time using auxiliary structures of o(n) bits. Navigation requires rank and select operations on the bit sequence, which are O(1) with precomputed lookup tables consuming sublinear extra space.
In balanced parentheses (BP) representation, the depth of a node is the excess of open parentheses over close parentheses at that position. Compute as: count of '(' minus count of ')' from start to node position. This equals the number of ancestors plus one. With rank data structures, this is O(1) after O(n) preprocessing.
Parallel Tree Traversal
9 questionsThe main challenge is diverging traversals where different SIMD lanes follow different paths, causing poor utilization. When one lane goes left and another goes right, both paths must be executed, wasting half the SIMD width. This divergence is inherent to tree structures where traversal depends on data comparisons at each node.
Dynamic sorting achieves average speedups of 2.78x over baseline by improving SIMD utilization to near-ideal levels. The technique reorders traversals based on previous behavior, grouping queries that follow similar paths together. This allows SIMD lanes to execute in lockstep rather than diverging, maximizing vector unit utilization.
Poker uses permutation-based SIMD execution with path encoding to vectorize multiple queries over B+ trees. It combines vector loads with path-encoding-based permutations to hide memory latency while minimizing key comparisons. Poker achieves 2.11x speedup with single thread and 2.28x with eight threads on AVX2 processors, without modifying the B+ tree structure.
AVX (256-bit) provides 1.1x to 1.3x speedup over SSE (128-bit) for tree ensemble evaluation, less than the theoretical 2x. The reduced gain is due to larger padding costs for AVX registers and increased memory bandwidth pressure. Despite this, AVX implementations achieve 2.3x-18.3x overall speedup compared to scalar baselines.
Modify node layout so k-1 separator keys can be compared in parallel with one SIMD instruction, where k depends on data type and SIMD width. For 4-byte integers with 256-bit AVX2, compare 8 keys simultaneously. Store keys contiguously within nodes and align to SIMD boundaries. This reduces comparisons per node from O(log k) to O(1).
SPMD (Single Program Multiple Data) executes the same traversal code on multiple data items simultaneously, similar to GPU programming. Use it via Intel ISPC compiler for portable SIMD code that works on SSE, AVX, and Xeon Phi. It is ideal for N-body simulations and ray tracing where many independent traversals occur. A single source compiles to efficient SIMD for each target.
PSB (Parallel Scan and Backtrack) traverses hierarchical tree structures on GPUs without stack overflow or warp divergence problems. It performs linear scanning of sibling leaf nodes to increase SIMD utilization. PSB consistently outperforms branch-and-bound kNN query processing for clustered datasets by reducing thread divergence within warps.
Traversal splicing is a locality transformation that dynamically reorders tree traversals based on previous behavior. When traversals diverge, splicing groups queries following similar paths together, enabling efficient SIMD execution. This can be cast as scheduling for SIMD where queries with similar traversal patterns execute together, achieving near-ideal SIMD utilization for originally diverging workloads.
Point blocking groups multiple tree traversal queries together and processes them in lockstep at each tree level. This exposes a loop structure where the same tree node operation is applied to multiple queries simultaneously, enabling SIMD vectorization. The blocking transforms irregular per-query traversals into regular batched operations amenable to vector instructions.
Perfect Binary Tree Indexing
8 questionsA perfect binary tree of height h contains exactly 2^(h+1) - 1 total nodes. For example, height 0 has 1 node, height 1 has 3 nodes, height 2 has 7 nodes, and height 3 has 15 nodes. This formula derives from the geometric series sum: 1 + 2 + 4 + ... + 2^h = 2^(h+1) - 1.
A perfect binary tree has exactly 2^d nodes at level d, where level 0 is the root. Level 0 has 1 node, level 1 has 2 nodes, level 2 has 4 nodes, and so on. This exponential growth is why the last level contains more than half of all nodes in the tree.
The height h of a perfect binary tree with N nodes is h = log2(N + 1) - 1. Equivalently, h = floor(log2(N)) for any complete or nearly complete binary tree. For example, a tree with 15 nodes has height log2(16) - 1 = 3. This is O(log N) height.
A perfect binary tree of height h has exactly 2^h leaf nodes. The leaf nodes are all at the last level. Additionally, the number of leaf nodes equals the number of internal (non-leaf) nodes plus 1. For a tree with N total nodes, the leaf count is (N + 1) / 2.
For a complete binary tree with n nodes, subtree size of node i requires computing how many indices in range [i, n) are descendants. For a perfect tree of height h, subtree rooted at depth d has 2^(h-d+1) - 1 nodes. For non-perfect trees, count nodes at each level using min(2^level, remaining_nodes). This is O(log n) calculation.
For 0-based indexing, the level of node at index i is floor(log2(i + 1)). For 1-based indexing, the level is floor(log2(i)). This can be computed efficiently using the bit-scan-reverse (BSR) instruction or compiler builtin __builtin_clz() to find the position of the highest set bit, which takes 1-3 cycles on modern CPUs.
A perfect binary tree of height h has 2^h - 1 internal (non-leaf) nodes. This equals the total nodes (2^(h+1) - 1) minus leaf nodes (2^h). Equivalently, for a tree with N total nodes, internal nodes = (N - 1) / 2 = N - leaf_count. Internal nodes always equal leaf nodes minus one.
For 0-based indexing, the first node at level d is at index 2^d - 1. For 1-based indexing, it is at index 2^d. For example, in 0-based indexing: level 0 starts at index 0, level 1 at index 1, level 2 at index 3, and level 3 at index 7.
Batch Tree Query Processing
8 questionsBatch processing allows multiple queries to share I/O, CPU, and memory resources, reducing total processing time. When queries access the same tree nodes, batching amortizes the cost of loading nodes into cache. PostgreSQL 17's B-tree bulk scan feature shows 30% throughput improvement and 20% latency reduction by processing multiple index lookups together.
PostgreSQL 17's nbtree ScalarArrayOp execution considers all input values during traversal. When multiple values land on the same leaf page, they are retrieved together, avoiding repetitive traversals. This yields approximately 30% throughput improvement (1,238 to 1,575 RPS) and 20% latency reduction (8ms to 6.3ms) for IN-clause queries.
Optimal batch B+ tree construction requires exactly one disk access per B+ tree page, achieved by simultaneously processing all key values for each page in a single access. This avoids overhead from accessing the same page multiple times that occurs with repeated single-key insertions. The approach is optimal because you cannot build a tree with fewer accesses than pages.
Optimal batch size increases with core count since larger batches can be processed in parallel without added delay. For 8-16 cores, batch sizes of 64-256 queries work well. The optimal size balances parallelism (larger batches) against latency (smaller batches). Skewed workloads benefit more from larger batches due to increased opportunity for sharing hot nodes.
Bulk Synchronous Parallel (BSP) based latch-free B+ tree processing handles queries in small batches without locks. As core count increases, larger batches can be processed in parallel without added delay. Larger batches expose more optimization opportunities beyond parallelism, especially with skewed query distributions where many queries access the same hot nodes.
The query batching problem partitions queries to maximize shared work between queries in the same batch. Queries accessing similar tree regions are grouped together so loaded nodes serve multiple queries. The goal is minimizing total I/O and cache misses rather than minimizing batch count. Optimal partitioning considers both query similarity and batch execution overhead.
Processing updates in batches achieves substantially higher improvements compared to one-at-a-time execution. The first asymptotically optimal bulk loading algorithm meets the lower bound of external sorting using a combination of buffer tree and weight balancing techniques. Weight balancing controls the degree of asynchrony between updates.
SQL Server's batch mode on rowstore enables batch execution for analytic workloads on B-tree indexes without requiring columnstore indexes. It processes rows in batches of approximately 900 rows, reducing CPU overhead from row-by-row processing. Batch mode supports bitmap filters for efficient join processing against on-disk heaps and B-tree indexes.
Implicit Binary Tree Representation
7 questionsFor 0-based indexing, the sibling of node at index i is at index i XOR 1 (i ^ 1). This flips the least significant bit, converting between 2k+1 and 2k+2. For the root (index 0), this formula gives index 1, which is not a valid sibling. Check i > 0 before computing. The XOR operation takes 1 CPU cycle.
A node at index i has a left child if 2i + 1 < n (for 0-based) or 2i < n (for 1-based), where n is the total number of nodes. For a complete binary tree, a node is a leaf if its left child index exceeds n-1. The check requires one shift, one add, and one comparison: roughly 3 cycles total.
In a Fenwick tree (Binary Indexed Tree), the parent of index i is i - (i & -i), which subtracts the lowest set bit. This differs from binary heap's floor(i/2). Fenwick tree parent moves toward index 0 by clearing progressively lower bits, creating a different tree structure optimized for prefix sum queries rather than heap operations.
The parent of a node at index i is located at index floor((i-1)/2). This formula uses integer division, which truncates toward zero. For index 0 (the root), this formula should not be applied as the root has no parent. The operation requires only a subtraction and a right shift: (i - 1) >> 1.
With 1-based indexing, the left child of a node at index i is located at index 2*i. This is simpler than 0-based indexing and only requires a single left shift operation (i << 1). This indexing scheme is commonly used in heap implementations because the parent formula also becomes simpler.
With 1-based indexing, the parent of a node at index i is located at index floor(i/2), which is simply i >> 1 using integer division. This is more efficient than the 0-based formula because it avoids the subtraction. For the root at index 1, this yields 0, indicating no valid parent.
For 0-based indexing: a node at index i is a left child if i is odd (i & 1 == 1), and a right child if i is even and i > 0. For 1-based indexing: a node is a left child if i is even (i & 1 == 0), and a right child if i is odd. This single-bit check executes in 1 CPU cycle.